x^2+20x-5525=0

Solution for x^2+20x-5525=0 equation:

x^2+20x-5525=0

a = 1; b = 20; c = -5525;
Δ = b2-4ac
Δ = 202-4·1·(-5525)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-150}{2*1}=\frac{-170}{2}
=-85
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+150}{2*1}=\frac{130}{2}
=65
$